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(C) We know that for a square matrix $M$ of order $n$, $|\operatorname{adj} M| = |M|^{n-1}$.Given $A$ is a square matrix of order $n=3$.First, conside

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$|A|^8$

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(C) We know that for a square matrix $M$ of order $n$, $|\operatorname{adj} M| = |M|^{n-1}$.Given $A$ is a square matrix of order $n=3$.First, consider the matrix $M = A^2$. The order of $M$ is $3$.Then, $|\operatorname{adj} M| = |M|^{3-1} = |M|^2 = (|A|^2)^2 = |A|^4$.Now, we need to find $|\operatorname{adj}(\operatorname{adj} A^2)|$.Let $K = \operatorname{adj} A^2$. Then $|K| = |A|^4$.Using the property $|\operatorname{adj} K| = |K|^{n-1}$, where $n=3$:$|\operatorname{adj} K| = |K|^{3-1} = |K|^2$.Substituting $|K| = |A|^4$:$|\operatorname{adj}(\operatorname{adj} A^2)| = (|A|^4)^2 = |A|^8$.

If $A$ is a square matrix of order $3$, then $|\operatorname{Adj}(\operatorname{Adj} A^2)|=$

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