If $f:[2, \infty) \rightarrow R$ is defined by $f(x)=x^2-4x+5$, then the range of $f$ is

The range of the function $f(x) = \frac{x^2}{x^2+1}$ is

Define the function $f: R \rightarrow R$ by $y = f(x) = x^2, x \in R$. Complete the table given below using this definition. What are the domain and range of this function? Also,draw the graph of $f$.

$x$	$-4$	$-3$	$-2$	$-1$	$0$	$1$	$2$	$3$	$4$
$y = f(x) = x^2$

The domain of the function $f(x) = \sqrt{\log_e\left(\frac{1}{x^2-4x+4}\right)} + \sin^{-1}(x^2-2)$ is

Let $D$ be the domain of the function $f(x) = \sin^{-1} \left(\log_{3x} \left(\frac{6+2 \log_3 x}{-5x}\right)\right)$. If the range of the function $g: D \rightarrow R$ defined by $g(x) = x - [x]$ (where $[x]$ is the greatest integer function) is $(\alpha, \beta)$,then $\alpha^2 + \frac{5}{\beta}$ is equal to

The domain of the function $f(x) = \sqrt{\frac{4-x^2}{[x]+2}}$,where $[x]$ denotes the greatest integer not more than $x$,is