Define the function $f: R \rightarrow R$ by $y = f(x) = x^2, x \in R$. Complete the table given below using this definition. What are the domain and range of this function? Also,draw the graph of $f$.
$x$ $-4$ $-3$ $-2$ $-1$ $0$ $1$ $2$ $3$ $4$
$y = f(x) = x^2$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The completed table is as follows:
$x$ $-4$ $-3$ $-2$ $-1$ $0$ $1$ $2$ $3$ $4$
$y = f(x) = x^2$ $16$ $9$ $4$ $1$ $0$ $1$ $4$ $9$ $16$

Domain of $f = R$ (the set of all real numbers).
Range of $f = [0, \infty)$ (the set of all non-negative real numbers).

Explore More

Similar Questions

The domain of the function $\sqrt{\log({x^2} - 6x + 6)}$ is

The domain of the function $f(x) = \sqrt{\frac{x-7}{9-x}}$ is

The domain of the function $f(x) = \frac{1}{\sqrt{[x]^2 - [x] - 2}}$ is, where $[x]$ denotes the greatest integer function.

The domain of the function $f(x) = \frac{1}{\log_{10}(1 - x)} + \sqrt{x + 2}$ is

The range of the function $f(x)=-\sqrt{5-6x-x^2}$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo