If f(x)=|x-1|+|x-2|, then f^{prime}(-2023)+f^ | vedclass

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(C) The function is defined as $f(x) = |x-1| + |x-2|$.We analyze the derivative $f^{\prime}(x)$ in different intervals:$1$. For $x < 1$, $f(x) = -(x-1

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(C) The function is defined as $f(x) = |x-1| + |x-2|$.We analyze the derivative $f^{\prime}(x)$ in different intervals:$1$. For $x Since $-2023 $2$. For $1 Since $1 $3$. For $x > 2$, $f(x) = (x-1) + (x-2) = 2x - 3$, so $f^{\prime}(x) = 2$.Since $2023 > 2$, $f^{\prime}(2023) = 2$.Summing these values: $f^{\prime}(-2023) + f^{\prime}\left(\frac{2024}{2023}\right) + f^{\prime}(2023) = -2 + 0 + 2 = 0$.

If $f(x)=|x-1|+|x-2|$, then $f^{\prime}(-2023)+f^{\prime}\left(\frac{2024}{2023}\right)+f^{\prime}(2023)=$

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