If $\frac{x^3}{(2x-1)(x+2)(x-3)} = A + \frac{B}{2x-1} + \frac{C}{x+2} + \frac{D}{x-3}$, then $A$ is equal to

  • A
    $\frac{1}{2}$
  • B
    $-\frac{1}{50}$
  • C
    $-\frac{8}{25}$
  • D
    $\frac{27}{25}$

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