If $2 x^2-3 x y+y^2+x+2 y-8=0$, then $\frac{d y}{d x}$ is equal to

  • A
    $\frac{3 y-4 x-1}{2 y-3 x+2}$
  • B
    $\frac{3 y+4 x+1}{2 y+3 x+2}$
  • C
    $\frac{3 y-4 x+1}{2 y-3 x-2}$
  • D
    $\frac{3 y-4 x+1}{2 y+3 x+2}$

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