If $e^{it} = \cos t + i \sin t$ and $e^{-it} = \cos t - i \sin t$, then $\cosh(x + iy) - \cosh(x - iy) =$

  • A
    $2 \sinh x \sinh y$
  • B
    $2i \sinh x \sin y$
  • C
    $2 \cosh x \cos y$
  • D
    $2i \sinh x \cos y$

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