If bar{a} = (x + 2y - 3) bar{i} + (2x - y + 3 | vedclass

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(C) Given that $\bar{a} = 2 \bar{b}$.Substituting the components of $\bar{a}$ and $\bar{b}$:$(x + 2y - 3) \bar{i} + (2x - y + 3) \bar{j} = 2[(3x - 2y)

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$8$

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(C) Given that $\bar{a} = 2 \bar{b}$.Substituting the components of $\bar{a}$ and $\bar{b}$:$(x + 2y - 3) \bar{i} + (2x - y + 3) \bar{j} = 2[(3x - 2y) \bar{i} + (x - y + 1) \bar{j}]$Equating the coefficients of $\bar{i}$ and $\bar{j}$:$1) x + 2y - 3 = 2(3x - 2y) \implies x + 2y - 3 = 6x - 4y \implies 5x - 6y = -3$$2) 2x - y + 3 = 2(x - y + 1) \implies 2x - y + 3 = 2x - 2y + 2 \implies y = -1$Substitute $y = -1$ into the first equation:$5x - 6(-1) = -3 \implies 5x + 6 = -3 \implies 5x = -9 \implies x = -9/5$We need to find $y - 5x$:$y - 5x = -1 - 5(-9/5) = -1 + 9 = 8$.

If $\bar{a} = (x + 2y - 3) \bar{i} + (2x - y + 3) \bar{j}$ and $\bar{b} = (3x - 2y) \bar{i} + (x - y + 1) \bar{j}$ are two vectors such that $\bar{a} = 2 \bar{b}$, then $y - 5x =$

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