If $A(1,2,3), B(3,7,-2), C(6,7,7)$ and $D(-1,0,-1)$ are points in a plane, then the vector equation of the line passing through the centroids of $\triangle ABD$ and $\triangle ACD$ is

  • A
    $\vec{r}=(2 \hat{i}-\hat{j})+t(\hat{j}+4 \hat{k})$
  • B
    $\vec{r}=(1+t) \hat{i}+3 \hat{j}+3 t \hat{k}$
  • C
    $\vec{r}=(2 \hat{i}+3 \hat{j}+3 \hat{k})+t(\hat{i}+3 \hat{j})$
  • D
    $\vec{r}=(\hat{i}+\hat{j}+\hat{k})+t(2 \hat{i}-\hat{j})$

Explore More

Similar Questions

Find the foot of the perpendicular drawn from the point $A(1, 0, 3)$ to the line joining the points $B(4, 7, 1)$ and $C(3, 5, 3)$.

The equation of the line passing through the point $(-1, 3, -2)$ and perpendicular to each of the lines $\frac{x}{1} = \frac{y}{2} = \frac{z}{3}$ and $\frac{x+2}{-3} = \frac{y-1}{2} = \frac{z+1}{5}$ is

The Cartesian equation of the line which passes through the points $(3,1,2)$ and $(-1,2,1)$ is

If the direction cosines of two lines are given by $l+m+n=0$ and $mn-2lm-2nl=0$,then the acute angle between those lines is

The equation of a line passing through the point $(2, 4, 6)$ and parallel to the line $3x + 4 = 4y - 1 = 1 - 4z$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo