If $A$ and $B$ are two events such that $P(A | B) = 0.6$, $P(B | A) = 0.3$, and $P(A) = 0.1$, then $P(\bar{A} \cap \bar{B})$ equals:

  • A
    $0.88$
  • B
    $0.12$
  • C
    $0.6$
  • D
    $0.4$

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$E_1$ and $E_2$ are two independent events of a random experiment such that $P(E_1) = \frac{1}{2}$ and $P(E_1 \cup E_2) = \frac{2}{3}$. Match the items of List-$I$ with the items of List-$II$.
List-$I$List-$II$
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$D$. $P(\bar{E}_1 \cup \bar{E}_2)$$(iv)$ $\frac{1}{6}$
$(v)$ $\frac{2}{3}$

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