If $\alpha, \beta$ are the roots of $x^2-a(x-1)+b=0$, then the value of $\frac{1}{\alpha^2-a \alpha}+\frac{1}{\beta^2-a \beta}+\frac{2}{a+b}$ is:

  • A
    $\frac{4}{a+b}$
  • B
    $\frac{1}{a+b}$
  • C
    $0$
  • D
    $-1$

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