If $x y^{\prime}+y-e^x=0$ and $y(a)=b$, then $\lim _{x \rightarrow 1} y(x)$ is

  • A
    $e+2 a b-e^a$
  • B
    $e^2+a b-e^{-a}$
  • C
    $e-a b+e^a$
  • D
    $e+a b-e^a$ (where $y^{\prime}=\frac{d y}{d x}$)

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