If $f(x) = \begin{cases} x, & 0 < x < 1/2 \\ 1, & x = 1/2 \\ 1 - x, & 1/2 < x < 1 \end{cases}$,then which of the following is true?

  • A
    $\lim_{x \to 1/2^+} f(x) = 2$
  • B
    $\lim_{x \to 1/2^-} f(x) = 2$
  • C
    $f(x)$ is continuous at $x = 1/2$
  • D
    $f(x)$ is discontinuous at $x = 1/2$

Explore More

Similar Questions

Show that the function defined by $f(x)=|\cos x|$ is a continuous function.

If $f: R \rightarrow R$ is defined by $f(x) = \begin{cases} a^2 \cos^2 x + b^2 \sin^2 x, & x \leq 0 \\ e^{ax+b}, & x > 0 \end{cases}$ and is a continuous function,then:

If $f(x) = \max(\sin x, \sin^{-1}(\cos x))$,then

The function $f(x) = |x-2| + x$ is

At which points is the function $f(x) = \frac{x}{[x]}$,where $[.]$ denotes the greatest integer function,discontinuous?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo