If $y = \tan^{-1} \sqrt{\frac{1 + \sin 2x}{1 - \sin 2x}}$, then at $x = \frac{\pi}{6}$, the value of $\frac{dy}{dx}$ is

  • A
    $0$
  • B
    $1$
  • C
    $\frac{1}{2}$
  • D
    $\frac{\sqrt{3}}{2}$

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