Easy
If $y = \cot^{-1}(x^2)$,then $\frac{dy}{dx}$ is equal to
- A$\frac{2x}{1 + x^4}$
- B$\frac{2x}{\sqrt{1 + 4x}}$
- C$\frac{-2x}{1 + x^4}$
- D$\frac{-2x}{\sqrt{1 + x^2}}$
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