If $y = \sqrt[3]{\tan x + y}$, then $\frac{dy}{dx} =$

  • A
    $\frac{\sec^2 x}{3y^2 + 1}$
  • B
    $\frac{\sec^2 x}{3y^2 - 1}$
  • C
    $\frac{\tan x}{3y^2 - 1}$
  • D
    $\frac{\sec^2 x}{3y - 1}$

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