Easy
If $f(x) = x + 2,$ then $f'(f(x))$ at $x = 4$ is
- A$8$
- B$1$
- C$4$
- D$5$
Explore More
Similar Questions
Differentiate the function with respect to $x$: $\sin^{3} x + \cos^{6} x$
Medium
View SolutionGiven $f(x) = 4x^3 - 6x^2 \cos 2a + 3x \sin 2a \sin 6a + \sqrt{\ln(2a - a^2)}$,then:
Let $f:R \to R$ be such that $f(1) = 3$ and $f'(1) = 6$. Then $\lim_{x \to 0} \left\{ \frac{f(1 + x)}{f(1)} \right\}^{\frac{1}{x}}$ equals
DifficultIIT 2002
View SolutionIf $f: R \rightarrow R$ is an even function having derivatives of all orders, then which of the following is an odd function?
The value of $\frac{d}{dx}[|x - 1| + |x - 5|]$ at $x = 3$ is
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo