If {I_m} = int_1^x {(log x)^m} dx satisfies t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given ${I_m} = \int_1^x {(\log x)^m} dx$. Using integration by parts,let $u = (\log x)^m$ and $dv = dx$. Then $du = m(\log x)^{m-1} \cdot \frac{1}

Vedclass · Accepted Answer

$l = m$

Vedclass · Answer

(B) Given ${I_m} = \int_1^x {(\log x)^m} dx$. Using integration by parts,let $u = (\log x)^m$ and $dv = dx$. Then $du = m(\log x)^{m-1} \cdot \frac{1}{x} dx$ and $v = x$. ${I_m} = [x(\log x)^m]_1^x - \int_1^x x \cdot m(\log x)^{m-1} \cdot \frac{1}{x} dx$. ${I_m} = x(\log x)^m - m \int_1^x (\log x)^{m-1} dx$. ${I_m} = x(\log x)^m - m{I_{m-1}}$. Comparing this with the given relation ${I_m} = k - l{I_{m-1}}$,we get $k = x(\log x)^m$ and $l = m$. Thus,the correct option is $l = m$.

If ${I_m} = \int_1^x {(\log x)^m} dx$ satisfies the relation ${I_m} = k - l{I_{m - 1}}$,then:

Similar Questions

Integrate the function: $x \log x$

The value of $\int 2x^{1/3} \sin x^{2/3} dx$ is

$\int (\log x)^2 dx =$

$\int \frac{x + \sin x}{1 + \cos x} \, dx$ is equal to

The value of $\int x \sin x \sec ^{3} x \, dx$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module