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(A) We know that the event $A$ can be expressed as the union of two disjoint events: $A = (A \cap B) \cup (A \cap \bar{B})$.By the addition theorem of

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$0.1$

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(A) We know that the event $A$ can be expressed as the union of two disjoint events: $A = (A \cap B) \cup (A \cap \bar{B})$.By the addition theorem of probability,since these events are disjoint,we have $P(A) = P(A \cap B) + P(A \cap \bar{B})$.Rearranging the formula to solve for $P(A \cap \bar{B})$,we get $P(A \cap \bar{B}) = P(A) - P(A \cap B)$.Substituting the given values: $P(A \cap \bar{B}) = 0.25 - 0.15 = 0.1$.

If $A$ and $B$ are two events of a random experiment,$P(A) = 0.25$,$P(B) = 0.5$ and $P(A \cap B) = 0.15$,then $P(A \cap \bar{B}) = $

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