(B) The first law of thermodynamics is generally expressed as $\Delta Q = \Delta U + W_{by}$,where $W_{by}$ is the work done $BY$ the system.In this p

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$\Delta Q = \Delta U - \Delta W$

(B) The first law of thermodynamics is generally expressed as $\Delta Q = \Delta U + W_{by}$,where $W_{by}$ is the work done $BY$ the system.In this problem,$\Delta W$ is defined as the work done $ON$ the system.By sign convention,work done on the system is negative of work done by the system,so $W_{by} = -\Delta W$.Substituting this into the first law equation: $\Delta Q = \Delta U + (-\Delta W)$.Therefore,the correct expression is $\Delta Q = \Delta U - \Delta W$.

Class 11 Physics Thermodynamics First Law of Thermodynamics

Medium

If $\Delta Q$ and $\Delta W$ represent the heat supplied to the system and the work done on the system respectively,then the first law of thermodynamics can be written as,where $\Delta U$ is the change in internal energy.

A
$\Delta Q = \Delta U + \Delta W$
B
$\Delta Q = \Delta U - \Delta W$
C
$\Delta Q = \Delta W - \Delta U$
D
$\Delta Q = - \Delta W - \Delta U$

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Thermodynamics

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First Law of Thermodynamics

$A$ total of $48 \,J$ heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by $2^{\circ} C$. The work done by the gas is : (Given,$R=8.3 \,J \,K^{-1} \,mol^{-1}$.) (in $\,J$)

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Which of the following does not follow the first law of thermodynamics? $(W = \text{work}, Q = \text{heat}, \Delta U = \text{change in internal energy})$

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The latent heat of vaporization of water is $2240 \, J/g$. If the work done in the process of vaporization of $1 \, g$ is $168 \, J$,then the increase in internal energy is .... $J$.

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What is the net amount of heat entering the system in a cyclic process equivalent to?

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When heat energy of $1500 \; J$ is supplied to a gas at a constant pressure of $2.1 \times 10^5 \; N/m^2$,its volume increases by $2.5 \times 10^{-3} \; m^3$. The increase in the internal energy of the gas in Joules is ...... $J$.

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If $\Delta Q$ and $\Delta W$ represent the heat supplied to the system and the work done on the system respectively,then the first law of thermodynamics can be written as,where $\Delta U$ is the change in internal energy.

Similar Questions

$A$ total of $48 \,J$ heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by $2^{\circ} C$. The work done by the gas is : (Given,$R=8.3 \,J \,K^{-1} \,mol^{-1}$.) (in $\,J$)

Which of the following does not follow the first law of thermodynamics? $(W = \text{work}, Q = \text{heat}, \Delta U = \text{change in internal energy})$

The latent heat of vaporization of water is $2240 \, J/g$. If the work done in the process of vaporization of $1 \, g$ is $168 \, J$,then the increase in internal energy is .... $J$.

What is the net amount of heat entering the system in a cyclic process equivalent to?

When heat energy of $1500 \; J$ is supplied to a gas at a constant pressure of $2.1 \times 10^5 \; N/m^2$,its volume increases by $2.5 \times 10^{-3} \; m^3$. The increase in the internal energy of the gas in Joules is ...... $J$.

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