If E = at + bt^2,what is the temperature of i | vedclass

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(A) The thermo-electromotive force $(E)$ in a thermocouple is given by the equation $E = at + bt^2$,where $t$ is the temperature difference between th

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$ - \frac{a}{2b} $

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(A) The thermo-electromotive force $(E)$ in a thermocouple is given by the equation $E = at + bt^2$,where $t$ is the temperature difference between the junctions.At the temperature of inversion,the thermo-electromotive force $(E)$ reaches its maximum or minimum value,meaning the rate of change of $E$ with respect to $t$ is zero.Therefore,we set the derivative $\frac{dE}{dt} = 0$.$\frac{d}{dt}(at + bt^2) = 0$$a + 2bt = 0$Solving for $t$,we get $t = -\frac{a}{2b}$.Thus,the temperature of inversion is $t = -\frac{a}{2b}$.

If $E = at + bt^2$,what is the temperature of inversion?

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