यदि $f(a) = 2$,$f'(a) = 1$,$g(a) = -3$,$g'(a) = -1$ है,तो $\mathop {\lim }\limits_{x \to a} \,\frac{f(a)g(x) - f(x)g(a)}{x - a} = $

  • A
    $1$
  • B
    $6$
  • C
    $-5$
  • D
    $-1$

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Similar Questions

जब $x \rightarrow 0$ हो, तो $\left\{\frac{1}{x} \sqrt{1+x}-\sqrt{1+\frac{1}{x^{2}}}\right\}$ की सीमा है:

$\lim _{x \rightarrow \frac{\pi}{4}} \frac{8 \sqrt{2}-(\cos x+\sin x)^{7}}{\sqrt{2}-\sqrt{2} \sin 2 x}$ का मान ज्ञात कीजिए।

$\mathop {\lim }\limits_{\alpha \to \pi /4} \frac{{\sin \alpha - \cos \alpha }}{{\alpha - \frac{\pi }{4}}} = $

सीमा का मान ज्ञात कीजिए: $\mathop {\text{Limit}}\limits_{x \to 4} \frac{(\cos \alpha)^x - (\sin \alpha)^x - \cos 2\alpha}{x - 4}$,जहाँ $0 < \alpha < \frac{\pi}{2}$.

$\mathop {\lim }\limits_{x \to 0} \frac{2}{x}\log (1 + x)$ का मान किसके बराबर है?

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