Difficult
If $f$ and $g$ are differentiable functions such that $g'(a) = 2$ and $g(a) = b$,and if $f \circ g$ is an identity function,then $f'(b)$ has the value equal to:
- A$2/3$
- B$1$
- C$0$
- D$1/2$
Explore More
Similar Questions
At $x = \sqrt{\frac{\pi}{2}}$,find the value of $\frac{d}{dx} \cos(\sin(x^2))$.
Difficult
View SolutionIf $f(x) = \frac{x}{1+x}$ and $g(x) = f(f(x))$,then $g^{\prime}(x)$ is equal to
DifficultAP EAMCET 2014
View SolutionIf $y = x \sin x$ and $\frac{\frac{dy}{dx} - \frac{y}{x}}{x \frac{dy}{dx} - y}$ at $x = \alpha$ is $1$, then $\alpha =$
If $y = \frac{\sqrt{x^2 + 1} + \sqrt{x^2 - 1}}{\sqrt{x^2 + 1} - \sqrt{x^2 - 1}}$,then $\frac{dy}{dx} = $
Easy
View SolutionIf $f(1)=1$ and $f^{\prime}(1)=3$,then the derivative of $f(f(f(x)))+(f(x))^2$ at $x=1$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo