If a body contains 10^{24} electrons and 10^{ | vedclass

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(B) The charge of a proton on a body is $q_p = n_p e = 10^{26} 	imes 1.6 	imes 10^{-19} \ C = 1.6 	imes 10^7 \ C$. The charge of an electron on a b

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$1.58 	imes 10^7$

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(B) The charge of a proton on a body is $q_p = n_p e = 10^{26} 	imes 1.6 	imes 10^{-19} \ C = 1.6 	imes 10^7 \ C$. The charge of an electron on a body is $q_e = -n_e e = -10^{24} 	imes 1.6 	imes 10^{-19} \ C = -1.6 	imes 10^5 \ C$. The total charge $Q$ on the body is the sum of the charges of protons and electrons: $Q = q_p + q_e = (1.6 	imes 10^7) - (1.6 	imes 10^5) \ C$. $Q = (160 	imes 10^5) - (1.6 	imes 10^5) \ C$. $Q = 158.4 	imes 10^5 \ C = 1.584 	imes 10^7 \ C$. Rounding to two significant figures,we get $Q \approx 1.58 	imes 10^7 \ C$.

If a body contains $10^{24}$ electrons and $10^{26}$ protons,the total amount of charge on the body is . . . . . . $C$.

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