(D) The given potential is $E = E_0 \sin(\omega t)$.The given current is $I = I_0 \sin(\omega t - \frac{\pi}{2})$.The phase difference $\phi$ between

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(D) The given potential is $E = E_0 \sin(\omega t)$.The given current is $I = I_0 \sin(\omega t - \frac{\pi}{2})$.The phase difference $\phi$ between the voltage and the current is $\phi = \omega t - (\omega t - \frac{\pi}{2}) = \frac{\pi}{2}$ or $90^{\circ}$.The average power consumption in an $AC$ circuit is given by the formula $P = E_{rms} I_{rms} \cos \phi$.Since $\phi = 90^{\circ}$,the power factor $\cos \phi = \cos(90^{\circ}) = 0$.Therefore,the power consumption $P = E_{rms} I_{rms} \times 0 = 0$.

Class 12 Physics Alternating Current Power in AC and Power Factor

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If a current $I$ given by $I = I_0 \sin(\omega t - \frac{\pi}{2})$ flows in an $AC$ circuit across which an $AC$ potential of $E = E_0 \sin(\omega t)$ has been applied,then the power consumption $P$ in the circuit will be

A
$P = \frac{E_0 I_0}{\sqrt{2}}$
B
$P = \sqrt{2} E_0 I_0$
C
$P = \frac{E_0 I_0}{2}$
D
$P = 0$

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Alternating Current

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Power in AC and Power Factor

In an $a.c.$ circuit,the voltage applied is $E = E_o \sin \omega t$. The resulting current in the circuit is $I = I_o \sin \left( \omega t - \frac{\pi}{2} \right)$. The power consumption in the circuit is given by:

EasyAIEEE 2007

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$A$ coil of inductive reactance $31\,\Omega$ has a resistance of $8\,\Omega$. It is placed in series with a capacitor of capacitive reactance $25\,\Omega$. The combination is connected to an $A$.$C$. source of $110\,V$. The power factor of the circuit is:

MediumAIPMT 2006

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If the power factor in an $AC$ circuit changes from $\frac{1}{3}$ to $\frac{1}{9}$,then by what percent will the reactance change (approximately),if the resistance remains constant?

Difficult

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The power factor of an $ac$ circuit having resistance $(R)$ and inductance $(L)$ connected in series and an angular velocity $\omega$ is:

MediumAIEEE 2002

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In an $A.C.$ circuit containing $L, C, R$ in series,the ratio of true power to apparent power is ($Z=$ impedance of the circuit and $R$ is the resistance).

EasyMHT CET 2025

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If a current $I$ given by $I = I_0 \sin(\omega t - \frac{\pi}{2})$ flows in an $AC$ circuit across which an $AC$ potential of $E = E_0 \sin(\omega t)$ has been applied,then the power consumption $P$ in the circuit will be

Similar Questions

In an $a.c.$ circuit,the voltage applied is $E = E_o \sin \omega t$. The resulting current in the circuit is $I = I_o \sin \left( \omega t - \frac{\pi}{2} \right)$. The power consumption in the circuit is given by:

$A$ coil of inductive reactance $31\,\Omega$ has a resistance of $8\,\Omega$. It is placed in series with a capacitor of capacitive reactance $25\,\Omega$. The combination is connected to an $A$.$C$. source of $110\,V$. The power factor of the circuit is:

If the power factor in an $AC$ circuit changes from $\frac{1}{3}$ to $\frac{1}{9}$,then by what percent will the reactance change (approximately),if the resistance remains constant?

The power factor of an $ac$ circuit having resistance $(R)$ and inductance $(L)$ connected in series and an angular velocity $\omega$ is:

In an $A.C.$ circuit containing $L, C, R$ in series,the ratio of true power to apparent power is ($Z=$ impedance of the circuit and $R$ is the resistance).

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