If a focal chord of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$ meets its minor axis at the point $(0,3)$,then the perpendicular distance from the centre of the ellipse to this focal chord is

  • A
    $5$
  • B
    $\frac{2}{\sqrt{5}}$
  • C
    $1$
  • D
    $\frac{3}{\sqrt{2}}$

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