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(C) Let the equation of the line in intercept form be $\frac{x}{a} + \frac{y}{b} = 1$.The coordinates of the points where the line intersects the axes

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$2$

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(C) Let the equation of the line in intercept form be $\frac{x}{a} + \frac{y}{b} = 1$.The coordinates of the points where the line intersects the axes are $A(0, b)$ and $B(a, 0)$.Since the point $(\alpha, \beta)$ is the midpoint of the segment $AB$, we have:$\alpha = \frac{0 + a}{2} \Rightarrow a = 2\alpha$$\beta = \frac{b + 0}{2} \Rightarrow b = 2\beta$Substituting these values into the intercept form equation:$\frac{x}{2\alpha} + \frac{y}{2\beta} = 1$Multiplying both sides by $2$:$\frac{x}{\alpha} + \frac{y}{\beta} = 2$

If a straight line passes through the point $(\alpha, \beta)$ and the portion of the line intercepted between the axes is divided equally at that point, then $\frac{x}{\alpha} + \frac{y}{\beta}$ is

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