If a train runs at 40 text{ km/h},it reaches | vedclass

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(C) Let the correct time be $t$ hours and the distance be $d$ km.Case $1$: Speed $= 40 	ext{ km/h}$,Time taken $= (t + \frac{11}{60}) 	ext{ hours}$.

Vedclass · Accepted Answer

$19$

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(C) Let the correct time be $t$ hours and the distance be $d$ km.Case $1$: Speed $= 40 	ext{ km/h}$,Time taken $= (t + \frac{11}{60}) 	ext{ hours}$.So,$d = 40(t + \frac{11}{60}) \dots (i)$Case $2$: Speed $= 50 	ext{ km/h}$,Time taken $= (t + \frac{5}{60}) 	ext{ hours}$.So,$d = 50(t + \frac{5}{60}) \dots (ii)$Equating $(i)$ and $(ii)$:$40(t + \frac{11}{60}) = 50(t + \frac{5}{60})$$4(t + \frac{11}{60}) = 5(t + \frac{5}{60})$$4t + \frac{44}{60} = 5t + \frac{25}{60}$$t = \frac{44}{60} - \frac{25}{60} = \frac{19}{60} 	ext{ hours}$.Since $1 	ext{ hour} = 60 	ext{ minutes}$,$t = \frac{19}{60} 	imes 60 = 19 	ext{ minutes}$.

If a train runs at $40 \text{ km/h}$,it reaches its destination late by $11 \text{ minutes}$. But if it runs at $50 \text{ km/h}$,it is late by $5 \text{ minutes}$ only. The correct time (in $\text{minutes}$) for the train to complete the journey is

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