If an error of $0.02 \text{ cm}^2$ is found in the surface area of a sphere when its radius is measured as $10 \text{ cm}$, then the approximate error that occurs in the volume of the sphere, in cubic centimetres, is

The approximate value of $(0.007)^{\frac{1}{3}}$ is

Consider the following statements:
$A$ is the relative error in the area of a square when the relative error in its side is $0.4$.
$B$ is the relative error in the volume of a sphere when the relative error in its radius is $0.3$.
$C$ is the relative error in the surface area of a closed cylinder whose height is equal to its radius, when the relative error in its height is $0.2$.
$D$ is the approximate error in $y = x^2 + x - 3$ when $x = 2$ and $\delta x = 0.1$.
The ascending order of the values of errors in these statements is:

For a given function $y=f(x)$, $\delta y$ denotes the actual error in $y$ corresponding to an actual error $\delta x$ in $x$, and $dy$ denotes the approximate value of $\delta y$. If $y=f(x)=2x^2-3x+4$ and $\delta x=0.02$, then the value of $\delta y - dy$ when $x=5$ is

Find the approximate change in the surface area of a cube of side $x$ metres caused by decreasing the side by $1 \%.$

The approximate value of $\cos(30^{\circ} 30^{\prime})$ is,given that $1^{\circ} = 0.0175 \text{ rad}$ and $\cos 30^{\circ} = 0.8660$.