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(C) The velocity of light in a medium is given by $v = \frac{1}{\sqrt{\mu \epsilon}}$.Since $\mu = \mu_0 \mu_r$ and $\epsilon = \epsilon_0 \epsilon_r$

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) The velocity of light in a medium is given by $v = \frac{1}{\sqrt{\mu \epsilon}}$.Since $\mu = \mu_0 \mu_r$ and $\epsilon = \epsilon_0 \epsilon_r$,we have $v = \frac{1}{\sqrt{\mu_0 \mu_r \epsilon_0 \epsilon_r}} = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \cdot \frac{1}{\sqrt{\mu_r \epsilon_r}}$.Given that the velocity of light in vacuum is $c = \frac{1}{\sqrt{\mu_0 \epsilon_0}}$,we can write $v = \frac{c}{\sqrt{\mu_r \epsilon_r}}$.Given $\mu_r = \frac{10}{\pi}$ and $\epsilon_r = \frac{1}{0.0885 	imes 10^{-10}}$ (Note: $8.85 	imes 10^{-12} = 0.0885 	imes 10^{-10}$),let's calculate the product $\mu_r \epsilon_r$.Actually,using the provided values: $\mu_r \epsilon_r = \frac{10}{\pi} 	imes \frac{1}{0.0885} \approx 3.183 	imes 11.299 \approx 36$.Thus,$v = \frac{c}{\sqrt{36}} = \frac{c}{6}$.Therefore,$c = 6v$. The velocity of light in vacuum is $6$ times greater than the velocity in the medium.

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