If angles $A$,$B$,and $C$ of a $\Delta ABC$ are $75^o$,$45^o$,and $60^o$ respectively,then the ratio of the areas of $\Delta OBC$,$\Delta COA$,and $\Delta AOB$ respectively is [where $O$ is the circumcentre of the triangle].

  • A
    $\sqrt{3} + 1 : 2 : \sqrt{6}$
  • B
    $1 : 2 : \sqrt{3}$
  • C
    $2 + \sqrt{3} : 1 : \sqrt{3}$
  • D
    $\sqrt{3} : 1 : \sqrt{2}$

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