If both the roots of 25x^{2} - x(m - 2) - 1 = | vedclass

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(C) Let the roots of the quadratic equation $25x^{2} - x(m - 2) - 1 = 0$ be $\alpha$ and $-\alpha$ because they are opposite to each other.For a quadr

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$2$

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(C) Let the roots of the quadratic equation $25x^{2} - x(m - 2) - 1 = 0$ be $\alpha$ and $-\alpha$ because they are opposite to each other.For a quadratic equation $ax^{2} + bx + c = 0$,the sum of roots is given by $\alpha + \beta = -b/a$.Here,$a = 25$,$b = -(m - 2)$,and $c = -1$.Sum of roots: $\alpha + (-\alpha) = -[-(m - 2)] / 25$.$0 = (m - 2) / 25$.Multiplying both sides by $25$,we get $0 = m - 2$.Therefore,$m = 2$.

If both the roots of $25x^{2} - x(m - 2) - 1 = 0$ are opposite,then $m = \ldots$

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