If the degree of ionisation of KI_3 is 80%,th | vedclass

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(B) The dissociation of $KI_3$ in an aqueous solution is given by: $KI_3 \rightleftharpoons K^{+} + I_3^-$Here,the number of ions produced per formula

Vedclass · Accepted Answer

$1.8$

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(B) The dissociation of $KI_3$ in an aqueous solution is given by: $KI_3 ightleftharpoons K^{+} + I_3^-$Here,the number of ions produced per formula unit is $n = 2$.The degree of ionisation is $\alpha = 80\% = 0.8$.The van't Hoff factor $(i)$ is calculated using the formula: $i = 1 + (n - 1)\alpha$Substituting the values: $i = 1 + (2 - 1) 	imes 0.8$$i = 1 + 1 	imes 0.8 = 1.8$

If the degree of ionisation of $KI_3$ is $80\%$,then what will be its van't Hoff factor?

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