If the Earth suddenly stops rotating,then the | vedclass

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(B) The apparent weight $w'$ of an object of mass $m$ at the equator is given by the formula: $w' = mg - m \omega^2 R$,where $g$ is the acceleration d

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Increase by $m \omega^2 R$

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(B) The apparent weight $w'$ of an object of mass $m$ at the equator is given by the formula: $w' = mg - m \omega^2 R$,where $g$ is the acceleration due to gravity,$\omega$ is the angular speed of the Earth,and $R$ is the radius of the Earth.When the Earth is rotating,the effective weight is reduced by the centrifugal force $m \omega^2 R$.If the Earth suddenly stops rotating,the angular speed $\omega$ becomes $0$.Consequently,the new apparent weight $w''$ becomes $w'' = mg$.Comparing the two,the weight increases by the magnitude of the centrifugal force,which is $m \omega^2 R$.Therefore,the weight of the object increases by $m \omega^2 R$.

If the Earth suddenly stops rotating,then the weight of an object of mass $m$ at the equator will $[\omega$ is the angular speed of the Earth and $R$ is its radius]

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