If an excess of $NH_4OH$ is added to a $CuSO_4$ solution,it forms a deep blue coloured complex which is:

  • A
    $[Cu(NH_3)_4]SO_4$
  • B
    $[Cu(NH_3)_2]SO_4$
  • C
    $[Cu(NH_4)_4]SO_4$
  • D
    $[Cu(NH_4)_2]SO_4$

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