The reaction of Pb(NO_3)_2 and NaCl in water | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction between $Pb(NO_3)_2$ and $NaCl$ produces a white precipitate of $PbCl_2$ according to the equation:$Pb(NO_3)_2(aq) + 2NaCl(aq) \right

Vedclass · Accepted Answer

$[PbCl_4]^{2-}$

Vedclass · Answer

(C) The reaction between $Pb(NO_3)_2$ and $NaCl$ produces a white precipitate of $PbCl_2$ according to the equation:$Pb(NO_3)_2(aq) + 2NaCl(aq) \rightarrow PbCl_2(s) + 2NaNO_3(aq)$When excess $HCl$ is added to this precipitate,it dissolves due to the formation of a soluble complex ion,tetrachloroplumbate$(II)$,represented as $[PbCl_4]^{2-}$:$PbCl_2(s) + 2Cl^-(aq) \rightarrow [PbCl_4]^{2-}(aq)$Thus,the dissolution is due to the formation of $[PbCl_4]^{2-}$.

The reaction of $Pb(NO_3)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration. The dissolution of the precipitate is due to the formation of

Similar Questions

The brown ring test for $NO_2^-$ and $NO_3^-$ is due to the formation of a complex ion with the formula:

Select the correct statement regarding the $[Ni(DMG)_2]$ complex compound.

Which one of the following metal complexes is most stable?

Which of the following has the maximum ionic conductivity?

The brown ring test for $NO_2^-$ and $NO_3^-$ ions is due to the formation of which of the following complex ions?

Vedclass Test Series

Exam Paper Generator

Online Exam Module