The brown ring test for $NO_2^-$ and $NO_3^-$ is due to the formation of a complex ion with the formula:

  • A
    $[Fe(H_2O)_6]^{2+}$
  • B
    $[Fe(NO)(CN)_5]^{2+}$
  • C
    $[Fe(H_2O)_5(NO)]^{2+}$
  • D
    $[Fe(H_2O)(NO)_5]^{2+}$

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