If in a Vernier callipers $10 \,VSD$ coincides with $8 \,MSD$,then the least count of the Vernier calliper is ............ $m$ [given $1 \,MSD = 1 \,mm$].

  • A
    $2 \times 10^{-4}$
  • B
    $1 \times 10^{-4}$
  • C
    $1 \times 10^{-3}$
  • D
    $8 \times 10^{-4}$

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