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Question

(B) When a $P-N$ junction is formed,electrons diffuse from the $N$-region to the $P$-region,and holes diffuse from the $P$-region to the $N$-region.Th

Vedclass · Accepted Answer

An electric field pointing from $N$-type to $P$-type side across the junction.

Vedclass · Answer

(B) When a $P-N$ junction is formed,electrons diffuse from the $N$-region to the $P$-region,and holes diffuse from the $P$-region to the $N$-region.This diffusion leaves behind ionized donor atoms in the $N$-region (positive charge) and ionized acceptor atoms in the $P$-region (negative charge) near the junction.This creates a depletion region and an internal electric field directed from the $N$-region to the $P$-region.This internal electric field opposes further diffusion of charge carriers,establishing a barrier potential.Therefore,even without an external voltage,an electric field exists pointing from the $N$-type side to the $P$-type side.

If no external voltage is applied across a $P-N$ junction,there would be:

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