If one root of $5x^2 + 13x + k = 0$ is the reciprocal of the other,then $k = $

  • A
    $0$
  • B
    $5$
  • C
    $1/6$
  • D
    $6$

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If the product of the roots of the equation ${x^2} - 3kx + 2{e^{2\log k}} - 1 = 0$ is $7$,then for what value of $k$ will its roots be real?

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The equation formed by decreasing each root of $ax^2 + bx + c = 0$ by $1$ is $2x^2 + 8x + 2 = 0$. Then:

$x=3$ is a solution of the equation $3x^{2} + (k-1)x + 9 = 0$ if $k$ has the value:

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