(A) For a quadratic equation $ax^2 + bx + c = 0$,the roots are given by the quadratic formula: $x = \frac{-b \pm \sqrt{D}}{2a}$,where $D = b^2 - 4ac$

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(A) For a quadratic equation $ax^2 + bx + c = 0$,the roots are given by the quadratic formula: $x = \frac{-b \pm \sqrt{D}}{2a}$,where $D = b^2 - 4ac$ is the discriminant.This formula provides two roots: $x_1 = \frac{-b + \sqrt{D}}{2a}$ and $x_2 = \frac{-b - \sqrt{D}}{2a}$.Since the question states that one root is $\frac{-b + \sqrt{D}}{2a}$,the other root must be $\frac{-b - \sqrt{D}}{2a}$.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

Easy

If one root of a quadratic equation $ax^2 + bx + c = 0$ is $\frac{-b + \sqrt{D}}{2a}$,then the other root is $\ldots \ldots \ldots \ldots$.

A
$\frac{-b - \sqrt{D}}{2a}$
B
$\frac{b + \sqrt{D}}{2a}$
C
$\frac{-c - \sqrt{D}}{2a}$
D
$\frac{c + \sqrt{D}}{2a}$

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If one root of a quadratic equation $ax^2 + bx + c = 0$ is $\frac{-b + \sqrt{D}}{2a}$,then the other root is $\ldots \ldots \ldots \ldots$.

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