If one root of the quadratic equation ix^2 - | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the quadratic equation $ix^2 - 2(i + 1)x + (2 - i) = 0$.Let the roots be $\alpha$ and $\beta$. We are given $\beta = 2 - i$.The product of t

Vedclass · Accepted Answer

$-i$

Vedclass · Answer

(A) Given the quadratic equation $ix^2 - 2(i + 1)x + (2 - i) = 0$.Let the roots be $\alpha$ and $\beta$. We are given $\beta = 2 - i$.The product of the roots for a quadratic equation $ax^2 + bx + c = 0$ is given by $\alpha \cdot \beta = \frac{c}{a}$.Here,$a = i$ and $c = 2 - i$.Therefore,$\alpha \cdot (2 - i) = \frac{2 - i}{i}$.Dividing both sides by $(2 - i)$,we get $\alpha = \frac{1}{i}$.Since $\frac{1}{i} = -i$,the other root is $\alpha = -i$.

If one root of the quadratic equation $ix^2 - 2(i + 1)x + (2 - i) = 0$ is $2 - i$,then the other root is

Similar Questions

The quadratic equation whose one root is $\frac{1}{2 + \sqrt{5}}$ will be

If both the roots of the quadratic equation ${x^2} - 2kx + {k^2} + k - 5 = 0$ are less than $5$,then $k$ lies in the interval

The condition for the roots of the equation $(c^2 - ab)x^2 - 2(a^2 - bc)x + (b^2 - ac) = 0$ to be equal is

Let $p, q \in Q$. If $2 - \sqrt{3}$ is a root of the quadratic equation $x^2 + px + q = 0$,then:

If $x = \sqrt{5} + 2$,then the value of $\frac{2x^2 - 3x - 2}{3x^2 - 4x - 3}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module