If only $1 \%$ of the total current is passed through a galvanometer of resistance $G$,then the resistance of the shunt is:

  • A
    $\frac{G}{25} \Omega$
  • B
    $\frac{G}{49} \Omega$
  • C
    $\frac{G}{2} \Omega$
  • D
    $\frac{G}{99} \Omega$

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Similar Questions

$A$ moving coil galvanometer of resistance $100 \ \Omega$ shows full-scale deflection when a current of $100 \ \mu A$ passes through it. If it is intended to show full-scale deflection when a current of $1 \ mA$ passes through it,the value of shunt resistance in ohms to be connected to the galvanometer is:

When a resistance of $5\,\Omega$ is shunted with a moving coil galvanometer,it shows a full scale deflection for a current of $250\,mA$. However,when a $1050\,\Omega$ resistance is connected with it in series,it gives full scale deflection for $25\,V$. The resistance of the galvanometer is $......\,\Omega$.

$A$ moving coil galvanometer is converted into an ammeter of range $0$ to $5 \, mA$. The galvanometer resistance is $90 \, \Omega$ and the shunt resistance has a value of $10 \, \Omega$. If there are $50$ divisions in the galvanometer-turned-ammeter on either side of zero, its current sensitivity is

Explain: "Increasing the current sensitivity may not necessarily increase the voltage sensitivity".

$100\,mA$ current gives a full scale deflection in a galvanometer of $2\,\Omega$ resistance. The resistance connected with the galvanometer to convert it into a voltmeter to measure $5\,V$ is ............... $\Omega$.

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