If the shortest wavelength of the $He^{+}$ ion in the Balmer series is $X \ m$,then the longest wavelength in the Paschen series of the $Li^{2+}$ ion is:

  • A
    $\frac{36}{5} \ X$
  • B
    $\frac{16}{7} \ X$
  • C
    $\frac{9}{5} \ X$
  • D
    $\frac{5}{9} \ X$

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