If the v_{rms} is 30 R^{1/2} at 27 ^circ C,th | vedclass

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(D) The formula for root mean square velocity is $v_{rms} = \sqrt{\frac{3RT}{M}}$.Given $v_{rms} = 30 R^{1/2}$ and $T = 27 ^\circ C = 300 \, K$.Squari

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$0.001$

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(D) The formula for root mean square velocity is $v_{rms} = \sqrt{\frac{3RT}{M}}$.Given $v_{rms} = 30 R^{1/2}$ and $T = 27 ^\circ C = 300 \, K$.Squaring both sides,we get $v_{rms}^2 = \frac{3RT}{M} = (30 R^{1/2})^2 = 900 R$.Equating the two expressions: $900 R = \frac{3RT}{M}$.Substituting $T = 300 \, K$: $900 R = \frac{3R 	imes 300}{M}$.$900 R = \frac{900 R}{M}$,which implies $M = 1 \, g/mol$.Converting to kilograms: $M = 1 \, g = 0.001 \, kg$.

If the $v_{rms}$ is $30 R^{1/2}$ at $27 ^\circ C$,then calculate the molar mass of the gas in kilograms.

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