If the $k^{\text{th}}$ term in the expansion of $\left(\frac{3}{2} x^2 - \frac{1}{3x}\right)^6$ is independent of $x$,then the numerically greatest term in the expansion of $\left(\frac{3}{2} x^2 - \frac{1}{3x}\right)^k$ when $x = \frac{2}{3}$ is:

  • A
    $\frac{40}{81}$
  • B
    $\left(\frac{7}{6}\right)^5$
  • C
    $\frac{20}{27}$
  • D
    $\left(\frac{7}{6}\right)^4$

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