If the circles $(x+a)^2+(y+b)^2=a^2$ and $(x+c)^2+(y+d)^2=d^2$ cut orthogonally,then $b(b-2d) =$

  • A
    $c(c-2a)$
  • B
    $c(2a-c)$
  • C
    $d(2c-a)$
  • D
    $a(a-2c)$

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