If the critical angle for total internal refl | vedclass

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(C) The relationship between the critical angle $C$ and the refractive index $\mu$ is given by $\sin C = \frac{1}{\mu}$.Given $C = 45^{\circ}$,we have

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$\frac{3}{\sqrt{2}} 	imes 10^{8} \; m/s$

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(C) The relationship between the critical angle $C$ and the refractive index $\mu$ is given by $\sin C = \frac{1}{\mu}$.Given $C = 45^{\circ}$,we have $\sin 45^{\circ} = \frac{1}{\mu}$.Since $\sin 45^{\circ} = \frac{1}{\sqrt{2}}$,it follows that $\frac{1}{\sqrt{2}} = \frac{1}{\mu}$,which implies $\mu = \sqrt{2}$.The velocity of light in a medium $v$ is related to the speed of light in vacuum $c$ by $v = \frac{c}{\mu}$.Substituting the values,$v = \frac{3 	imes 10^{8}}{\sqrt{2}} \; m/s$.

If the critical angle for total internal reflection from a medium to vacuum is $45^{\circ}$,then the velocity of light in the medium is,

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