If the distribution of molecular speeds of a | vedclass

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(C) The standard expressions for the speeds are:Most probable speed $(u_{mp})$ = $\sqrt{\frac{2RT}{M}}$Average speed $(u_{av})$ = $\sqrt{\frac{8RT}{\p

Vedclass · Accepted Answer

$1: 1.128: 1.224$

Vedclass · Answer

(C) The standard expressions for the speeds are:Most probable speed $(u_{mp})$ = $\sqrt{\frac{2RT}{M}}$Average speed $(u_{av})$ = $\sqrt{\frac{8RT}{\pi M}} \approx 1.128 	imes \sqrt{\frac{RT}{M}}$Root mean square speed $(u_{rms})$ = $\sqrt{\frac{3RT}{M}} \approx 1.224 	imes \sqrt{\frac{RT}{M}}$Taking the ratio $u_{mp} : u_{av} : u_{rms}$:$\sqrt{2} : \sqrt{\frac{8}{\pi}} : \sqrt{3}$$1.414 : 1.596 : 1.732$Dividing by $1.414$:$1 : 1.128 : 1.224$

If the distribution of molecular speeds of a gas is as per the figure shown below,then the ratio of the most probable,the average and the root mean square speeds,respectively,is

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