Points I,II and III in the following plot res | vedclass

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(D) The most probable velocity is given by the formula $V_{mp} = \sqrt{\frac{2RT}{M}}$,which implies $V_{mp} \propto \sqrt{\frac{T}{M}}$.Calculating t

Vedclass · Accepted Answer

$V_{mp}$ of $N_2$ $(300 \ K)$; $V_{mp}$ of $O_2$ $(400 \ K)$; $V_{mp}$ of $H_2$ $(300 \ K)$

Vedclass · Answer

(D) The most probable velocity is given by the formula $V_{mp} = \sqrt{\frac{2RT}{M}}$,which implies $V_{mp} \propto \sqrt{\frac{T}{M}}$.Calculating the relative values for the given gases:$1$. For $N_2$ $(300 \ K)$: $\sqrt{\frac{300}{28}} \approx \sqrt{10.71} \approx 3.27$$2$. For $O_2$ $(400 \ K)$: $\sqrt{\frac{400}{32}} = \sqrt{12.5} \approx 3.53$$3$. For $H_2$ $(300 \ K)$: $\sqrt{\frac{300}{2}} = \sqrt{150} \approx 12.25$Comparing these values,we get $V_{mp}(N_2, 300 \ K) Thus,point $I$ corresponds to $N_2$ $(300 \ K)$,point $II$ corresponds to $O_2$ $(400 \ K)$,and point $III$ corresponds to $H_2$ $(300 \ K)$.

Points $I$,$II$ and $III$ in the following plot respectively correspond to ($V_{mp}:$ most probable velocity).

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